5x(x^2+1)+4(x^2+1)=0

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Solution for 5x(x^2+1)+4(x^2+1)=0 equation:


Simplifying
5x(x2 + 1) + 4(x2 + 1) = 0

Reorder the terms:
5x(1 + x2) + 4(x2 + 1) = 0
(1 * 5x + x2 * 5x) + 4(x2 + 1) = 0
(5x + 5x3) + 4(x2 + 1) = 0

Reorder the terms:
5x + 5x3 + 4(1 + x2) = 0
5x + 5x3 + (1 * 4 + x2 * 4) = 0
5x + 5x3 + (4 + 4x2) = 0

Reorder the terms:
4 + 5x + 4x2 + 5x3 = 0

Solving
4 + 5x + 4x2 + 5x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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